Ques. A museum has an average of 640 visitors on each Saturdays and Sundays, while 310 visitors on other days. The average number of visitors per day in a month of 30 days beginning with a Saturday is
Anonymous Quiz
7%
(a) 560
22%
(b) 240
14%
(c) 620
57%
(d) 420
π6
Ans. (d) 420 | Explanation:
In a month of 30 days beginning with Saturday, we will have 5 Saturdays, 5 Sundays and 20 Other days.
Visitors on 5 Saturdays = 640 Γ 5 = 3200
Visitors on 5 Sundays = 640 Γ 5 = 3200
Visitors on Other days = 310 Γ 20 = 6200
So, Total number of visitors in 30 days = 3200 + 3200 + 6200 = 12600
Average number of visitors per day = 12600/30 = 420
Hence, option (d) is the correct answer.
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In a month of 30 days beginning with Saturday, we will have 5 Saturdays, 5 Sundays and 20 Other days.
Visitors on 5 Saturdays = 640 Γ 5 = 3200
Visitors on 5 Sundays = 640 Γ 5 = 3200
Visitors on Other days = 310 Γ 20 = 6200
So, Total number of visitors in 30 days = 3200 + 3200 + 6200 = 12600
Average number of visitors per day = 12600/30 = 420
Hence, option (d) is the correct answer.
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π5
Ques. Rent of a room is Rs. 9600, which is shared among Kallu, Malkhan, Ramu and Shyam. If contribution ratio of Kallu & Malkhan, Malkhan & Ramu and Ramu & Shyam is 1:2, 2:3 and 5:6 respectively, then what is the contribution of Malkhan in the rent?
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π4
Select the correct answer using the codes given below.
Anonymous Quiz
10%
(a) Rs. 1400
59%
(b) Rs. 2000
22%
(c) Rs. 1000
9%
(d) Rs. 1600
π6
Answer: (b) | Explanation:
Contribution ratio of Kallu and Malkhan = 1:2
Contribution ratio of Malkhan and Ramu = 2:3
So, Contribution ratio of Kallu, Malkhan and Ramu = 1:2:3 β¦β¦β¦.(i)
Contribution ratio of Ramu and Shyam = 5:6 β¦β¦β¦..(ii)
To make Contribution of Ramu equal in eqn (i) and (ii), we will multiply eqn (i) by 5 and eqn (ii) by 3.
Contribution ratio of Kallu, Malkhan and Ramu = [1:2:3] Γ 5 = 5:10:15
Contribution ratio of Ramu and Shyam = [5:6] Γ 3 = 15:18
So, Contribution ratio of Kallu, Malkhan, Ramu and Shyam = 5:10:15:18
β΄ Required contribution of Malkhan = 9600 Γ 10/(5+10+15+18) = Rs. 2000
Hence, option (b) is correct.
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Contribution ratio of Kallu and Malkhan = 1:2
Contribution ratio of Malkhan and Ramu = 2:3
So, Contribution ratio of Kallu, Malkhan and Ramu = 1:2:3 β¦β¦β¦.(i)
Contribution ratio of Ramu and Shyam = 5:6 β¦β¦β¦..(ii)
To make Contribution of Ramu equal in eqn (i) and (ii), we will multiply eqn (i) by 5 and eqn (ii) by 3.
Contribution ratio of Kallu, Malkhan and Ramu = [1:2:3] Γ 5 = 5:10:15
Contribution ratio of Ramu and Shyam = [5:6] Γ 3 = 15:18
So, Contribution ratio of Kallu, Malkhan, Ramu and Shyam = 5:10:15:18
β΄ Required contribution of Malkhan = 9600 Γ 10/(5+10+15+18) = Rs. 2000
Hence, option (b) is correct.
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π11
Ques. 100 people were divided into two groups of 40 and 60 people. If the average age of 40 people and 60 people is 50 years and 55 years respectively, what must be the average age of all the persons taken together?
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π6
Select the correct answer using the codes given below.
Anonymous Quiz
7%
(a) 45 years
13%
(b) 95 years
76%
(c) 53 years
4%
(d) 65 years
π6π₯1
Ans. C | Explanation:
Average age of 40 people is 50 years, and average age of 60 people is 55 years.
So, sum of the ages of 40 people = 40 Γ 50 = 2000 years
Sum of ages of 60 people = 60 Γ 55 = 3300 years
Required average age = (2000 + 3300)/(40 + 60) = 5300/100 = 53 years
Hence, option (c) is correct.
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Average age of 40 people is 50 years, and average age of 60 people is 55 years.
So, sum of the ages of 40 people = 40 Γ 50 = 2000 years
Sum of ages of 60 people = 60 Γ 55 = 3300 years
Required average age = (2000 + 3300)/(40 + 60) = 5300/100 = 53 years
Hence, option (c) is correct.
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π9
Ques. If 10% of x is 25% of the half of y, then what must be the value of y/x?
Anonymous Quiz
5%
(a) 3/4
11%
(b) 8/3
67%
(c) 4/5
17%
(d) 5/4
π5
Ans. C | Explanation:
This is simply a matter of breaking down the problem. 10 percent of x is 0.1x.
25 percent of half of y is 25 percent of 0.5y, which is 0.25 Γ 0.5y = y/8.
Now, as per the question,
x/10 = y/8
or y/x = 4/5
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This is simply a matter of breaking down the problem. 10 percent of x is 0.1x.
25 percent of half of y is 25 percent of 0.5y, which is 0.25 Γ 0.5y = y/8.
Now, as per the question,
x/10 = y/8
or y/x = 4/5
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π5
Ques. The price of an item is decreased by 10%, then by 20%, and finally by 30%. This is equivalent to:
Anonymous Quiz
27%
(a) Decreasing the price by 50.4%
21%
(b) Decreasing the price by 60%.
16%
(c) Decreasing the price by 40.5%
36%
(d) Decreasing the price by 49.6%
π3
Ans. D | Explanation:
Decreasing a price by 10%, then by 20%, and then by 30% is equivalent to taking 90% of a price, then taking 80% of the remaining price, and then taking 70% of that. That, in turn, is equivalent to multiplying the price by 0.90, then by 0.80, and then by 0.70.
For simplicity's sake, assume the initial price was Rs. 100. Then we can calculate the final price as follows:
Final price = 100 Γ 0.9 Γ 0.8 Γ 0.7 = Rs. 50.40
So, we essentially discounted the original price by Rs.49.60, which is 49.6%.
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Decreasing a price by 10%, then by 20%, and then by 30% is equivalent to taking 90% of a price, then taking 80% of the remaining price, and then taking 70% of that. That, in turn, is equivalent to multiplying the price by 0.90, then by 0.80, and then by 0.70.
For simplicity's sake, assume the initial price was Rs. 100. Then we can calculate the final price as follows:
Final price = 100 Γ 0.9 Γ 0.8 Γ 0.7 = Rs. 50.40
So, we essentially discounted the original price by Rs.49.60, which is 49.6%.
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π5
Ques. When processing flower-nectar into honeybees' extract, a considerable amount of water gets wasted. How much flower-nectar must be processed to yield 1 kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water?
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π2
Select the correct answer using the codes given below.
Anonymous Quiz
12%
(a) 1.5 kg
55%
(b) 1.7 kg
25%
(c) 3.33 kg
8%
(d) 2.2 kg
π3
Ans. B | Explanation:
Let the amount of flower-nectar needed be x kg.
Flower-nectar contains 50% water. So, flower-nectar contains 50% of non-watery part.
Honey contains 15% water. So, amount of non-watery part in the honey will be 85%.
When processing flower-nectar into honeybees' extract, only the water is lost during processing.Hence, the non-watery part in flower-nectar should be equal to the non-watery part in honey.
β΄ 50% of the Amount of flower-nectar needed = 85% of the Amount of honey
Or 0.5 Γ x = 0.85 Γ 1 kg
Or x = (0.85/0.5) Γ 1 kg = 1.7 kg
Therefore, the amount of flower-nectar needed is 1.7 kg.
Hence, option (b) is correct.
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Let the amount of flower-nectar needed be x kg.
Flower-nectar contains 50% water. So, flower-nectar contains 50% of non-watery part.
Honey contains 15% water. So, amount of non-watery part in the honey will be 85%.
When processing flower-nectar into honeybees' extract, only the water is lost during processing.Hence, the non-watery part in flower-nectar should be equal to the non-watery part in honey.
β΄ 50% of the Amount of flower-nectar needed = 85% of the Amount of honey
Or 0.5 Γ x = 0.85 Γ 1 kg
Or x = (0.85/0.5) Γ 1 kg = 1.7 kg
Therefore, the amount of flower-nectar needed is 1.7 kg.
Hence, option (b) is correct.
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π9
Ques. If Ξ± and Ξ² are two real numbers such that Ξ± + Ξ² = - q/p and Ξ±Ξ² = r/p, where 0<p<q<r (p, q, r are natural numbers), then which one of the following alternatives represents the highest value?
Anonymous Quiz
6%
(a) 1 / (Ξ± + Ξ²)
32%
(b) (1/ Ξ±) + (1/Ξ²)
43%
(c) β 1/ (Ξ±Ξ²)
19%
(d) Ξ±Ξ²/(Ξ± + Ξ²)
π6
Ans. C | Explanation:
It is given that Ξ± + Ξ² = - q/p and Ξ±Ξ² = r/p, where 0<p<q<r
So, letβs assume p = 1, q = 2 and r = 3.
Putting these values in answer options, we get
(A) 1 / (Ξ± + Ξ²) = - p/q = - (1/2)
(B) (1/ Ξ±) + (1/ Ξ²) = (Ξ± + Ξ²)/ Ξ±Ξ² = -(q/p) Γ (p/r) = - (q/r) = - (2/3)
(C) β 1/ (Ξ±Ξ²) = -(p/r) = - (1/3)
(D) Ξ±Ξ²/(Ξ± + Ξ²) = r/p Γ (-p/q)= - r/q = - (3/2)
We can see that, - (1/3) is the greatest among the above values.
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It is given that Ξ± + Ξ² = - q/p and Ξ±Ξ² = r/p, where 0<p<q<r
So, letβs assume p = 1, q = 2 and r = 3.
Putting these values in answer options, we get
(A) 1 / (Ξ± + Ξ²) = - p/q = - (1/2)
(B) (1/ Ξ±) + (1/ Ξ²) = (Ξ± + Ξ²)/ Ξ±Ξ² = -(q/p) Γ (p/r) = - (q/r) = - (2/3)
(C) β 1/ (Ξ±Ξ²) = -(p/r) = - (1/3)
(D) Ξ±Ξ²/(Ξ± + Ξ²) = r/p Γ (-p/q)= - r/q = - (3/2)
We can see that, - (1/3) is the greatest among the above values.
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π6
πPosition of Letters in English Alphabet
βοΈ Sometimes a word or a sentence is coded by changing the position of English alphabet letters according to a definite pattern, so it is necessary to remember the positions of all the letters in English alphabetical order, both in forward and backward order.
π Important for Coding - Decoding QuestionsβΌοΈ
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βοΈ Sometimes a word or a sentence is coded by changing the position of English alphabet letters according to a definite pattern, so it is necessary to remember the positions of all the letters in English alphabetical order, both in forward and backward order.
π Important for Coding - Decoding QuestionsβΌοΈ
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π11β€2
Q. If 'white' is called 'blue', 'blue' is called 'red', 'red' is called 'yellow', 'yellow, is called 'green', 'green' is called 'black', 'black' is called 'violet' and 'violet' is called 'orange', then what would be the colour of human blood?
Anonymous Quiz
15%
(a) Red
7%
(b) Green
73%
(c) Yellow
5%
(d) Violet
π13
Circular Arrangement of Letters in English Alphabet
If we have to find the letter one placed forward to A, then the letter will be B and this result can be found out by using either linear or circular arrangement but when one is asked to find the letter which is one letter backward of A (Z is one letter backward A) or one letter forward of Z (A is the one letter forward Z), then only circular arrangement gives such results.
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If we have to find the letter one placed forward to A, then the letter will be B and this result can be found out by using either linear or circular arrangement but when one is asked to find the letter which is one letter backward of A (Z is one letter backward A) or one letter forward of Z (A is the one letter forward Z), then only circular arrangement gives such results.
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π13