TCS exam Answer

:
8 2125

7 800000

11 1200

TCS IRA
Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
13.
14.
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
27.
28.
29.
30.
31.
32.
33.
34.
35.
36.
37.
38.
39.
40.
41.
42.
43.
44.
45.
46.
47. D
48. A
49. D
50. B

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TCS IRA

Java
1. All
2. Excellence
3. All the evidence
4. Deployment lctn
5. Truesophisticated
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
27.
28.
29.
30.
31.
32.
33.
34.
35.
36.
37.
38.
39.
40.
41.
42.
43.
44.
45.
46.
47.
48.
49.
50.

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TCS IRA

Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
47. D
48. A
49. D
50. B

26. A
27. B
28. B
29. 1
30.1
31.b
32.b
43.a
44.a
45.a
46.d

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TCS IRA

Java
1. All
2. Excellence
3. All the evidence
4. Deployment lctn
5. Truesophisticated
6.
7.
8.
9.
10. Knife in right
11.
12.
13.
14.
15.
16.
17.
18.
19. Returns all rows from left
20. 21



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TCS Python PRA
1.b
2.d
3.a
4.d
5.a
6.c
7.d
8.d
9.d
10.a
11.d
12.a
13.c
14.c
15.b
16.b
17.c
18.a
19.a
20.a
21.b
22.d
23.
24.
25.c
26.c
27.a
28.c
29.a
30.c

21 B
22 D
23 A
24 C
25 C

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TCS Java

1.bvszbcd
2.b grep tech
3.cp programs
4.pat$
5.sort -r
6.
7. A
8.
9. Truncate
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.C
22 44
23.
24. Nonevof these
25.radio button
26.b new
27.c
28.b
29.false
30.


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TCS Java PRA
fill this sheet sequence will be same..
1.bvszbcd
2.b grep tech
3.cp programs
4.pat$
5.sort -r
6.1
7. A
8.select distinct d name
9. Truncate
10.
11.
12.
13.
14.
15.
16.B
17.C object
18.all of above
19.A
20.C
21.C
22 44
23.B
24. Nonevof these
25.radio button
26.b new
27.c
28.b
29.false
30.true
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awk 'BEGIN{FS=",", count=0;}
{
if($3>=60)
count++;
{print $2,"#",$3;}
}
END { if(count!=0){print count;
}
else
{
print "No records found";
}}'


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awk 'BEGIN{FS="|", count=0;}
{
if($3>20)
{count+=$3;}
}
END { if(count!=0){print "Total count: " count;
}
else
{
print "No record found with matching criteria.";
}}'


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ZOHO Question No 1 Code
Language: C++


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ZOHO Question NO 2 Code
Language: C++


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ZOHO Question 3 Code
Language: C++


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Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
13.entire record

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PYTHON IRA
1. 2003
2. All of the options
3. Reinforcement learning
4. All the evidence
5.D
6.C
27.allof the above
44.byte code
45. Runtime environment

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Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
20. True
15.B

26. B
27. C
28. D
29. B
30. True
31. B
32. D
33.C
34. B
35. A
38. A
39. Default
44.byte code
45.runtime environment
47. A

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Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
20. True
14. Path
15.B
23. B
25.b

26. B
27. C
28. D
29. B
30. True
31. B
32. D
33.C
34. B
35. A
38. A
39. Default
44.byte code
45.runtime environment
47. A
50. Compilation error
48 . D

43 c

14.path

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Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
47. D
48. A
49. D
50. B

26. A
27. B
28. B
29. 1
30.1
31.b
32.b
43.a
44.a
45.a
46.d

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class Employee:
def _init_(self,n,d,s,lb):
self.name=n
self.designation=d
self.salary=s
self.leavesbalance=lb

class Organization:
def _init_(self,elist):
self.employee_list=elist

def display_leaves(self,name):
for i in self.employee_list:
if i.name==name:
for a,b in i.leavesbalance.items():
print(a,":",b)

def checkLeaveEligibility(self,ename,tl,nol):
for i in self.employee_list:
if i.name==ename:
for a,b in i.leavesbalance.items():
if a==tl:
if b>=nol:
i.leavesbalance[a]=b-nol
return 'True'
else:
return 'False'
return 'not found'
if _name_ == '_main_':
elist=[]
num=int(input())
for i in range(num):
leaves={}
name=input()
designation=input()
salary=int(input())
ltype=int(input())
for i in range(ltype):
key=input()
value=int(input())
leaves[key]=value
elist.append(Employee(name,designation,salary,leaves))
obj=Organization(elist)
empname=input()
Itype=input()
nol=int(input())
if(obj.checkLeaveEligibility(empname,Itype,nol)=='True'):
print("leave granted")
obj.display_leaves(empname)
elif(o.checkLeaveEligibility(empname,Itype,nol)=='False'):
print("leave not granted")
obj.display_leaves(empname)
elif(obj.checkLeaveEligibility(empname,Itype,nol)=='not found'):
print("leave not granted")
print("Employee not found")


Employee code

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awk ' BEGIN{FS=#;count=0;}{

if($4>300){
count=count+$3;}

}END{
print "Total count:" count;}
else
{
print "No soap found with cost above 300";
}
}'


Soap management unix

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class Food:
def init(self,name,protien,fat,carb):
self.name=name
self.protien=protien
self.fat=fat
self.carb=carb

class Nutrition:
def init(self,status,lfood):
self.status=status
self.lfood=lfood
def setEnergy(self):
result=[]
for i in lfood:
for k,v in status.items():

temp=(i.protien+i.fat+i.carb)
if(temp>=v[0] and temp<=v[1]):
result.append(str(i.name)+" - "+str(temp)+" - "+k)
if(len(result)==0):
return None
else:
return result
def getEnergyRichFood(self,checkenergy):
ans=[]
for i in lfood:
temp=(i.protien+i.fat+i.carb)
if(temp<=checkenergy):
ans.append(i.name+" : "+str(temp))
if(len(ans)==0):
return None
else:
return ans
n=int(input())
lfood=[]

for i in range(n):
name=input()
protien=float(input())
fat=float(input())
carb=float(input())
lfood.append(Food(name,protien,fat,carb))
status={}
cnt=int(input())
for i in range(cnt):
st=input()
l=[]
l.append(int(input()))
l.append(int(input()))
status[st]=tuple(l)
checkenergy=int(input())
obj=Nutrition(status,lfood)
result=obj.setEnergy()
ans=obj.getEnergyRichFood(checkenergy)
if(result!=None):
print("Energy of Food:")
for i in result:
print(i)
if(ans!=None):
print("Food within given criteria:")
for i in ans:
print(i)
else:
print("No Food Found")

Food code

python


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