Forwarded from < Ace Coding /> 🚀
Choose your answer for the above code.
Anonymous Quiz
31%
🅰️ i: 4
21%
🅱️ i: 5
18%
🅾️ i: 6
18%
❓ Infinite loop
13%
❌ Compilation error
Forwarded from < Ace Coding /> 🚀
Predict the output:
int x = 5;
int y = 10;
(x > y ? x : y) = 50;
cout << "x: " << x << ", y: " << y << endl;
Forwarded from < Ace Coding /> 🚀
Choose your answer for the above.
Anonymous Quiz
4%
🅰️ x: 50, y: 50
4%
🅱️ x: 10, y: 50
65%
🅾️ x: 5, y: 50
19%
❓ Undefined behavior
8%
❌ Compilation error
Forwarded from < Ace Coding /> 🚀
Predict the output:
int a = (3, 4, 1, 2);
cout << a ;
Forwarded from < Ace Coding /> 🚀
choose your answer for the above.
Anonymous Quiz
24%
🅰️ [3, 4, 1, 2]
0%
🅱️ [4, 2]
0%
🅾️ [3, 1]
6%
4
6%
2
12%
3
0%
1
18%
❓ Undefined behavior
35%
❌ Compilation error
Forwarded from < Ace Coding /> 🚀
📝 Types of Errors in a Program: 💥⚡️🔍
🌟🚀 @AceCoding Presents! 🚀🌟
💥 Compilation Error: (Cannot compile, cannot run)
Occurs when the code has syntax issues, preventing it from being compiled. Common examples include missing semicolons, mismatched parentheses, or undeclared variables.
Example: int x = ;
⚡️ Runtime Error: (Compiles but cannot run, compilation comes before code execution or running)
Happens while the program is running. It usually occurs due to illegal operations like division by zero, accessing invalid memory, or infinite loops.
Example: int x = 5 / 0;
🔍 Logical Error: (Code compiles and runs but won't result a correct output)
Occurs when the code runs without crashing, but it produces incorrect results due to flawed logic or assumptions. It can be tricky to spot as the program compiles and runs fine.
Example: int a = 5; int b = 2; cout << a - b; (Expecting multiplication but using subtraction)
🌟🚀 @AceCoding Presents! 🚀🌟
👍1
Forwarded from < Ace Coding /> 🚀
Predict the output of the following code snippets! 🤔
📝 Code Snippets: ```java String input = new String("hello"); System.out.println(input == "hello"); String input = "hello"; System.out.println(input == "hello"); ```
📝 Code Snippets: ```java String input = new String("hello"); System.out.println(input == "hello"); String input = "hello"; System.out.println(input == "hello"); ```
Anonymous Quiz
9%
A) True, False
45%
B) False, True
36%
C) True, True
9%
D) False, False
Forwarded from < Ace Coding /> 🚀
👆For the above question
String input = new String("hello");
System.out.println(input == "hello");
String input = "hello";
System.out.println(input == "hello");Forwarded from < Ace Coding /> 🚀
🔹How can you correctly compare the contents of two strings in Java?
Anonymous Quiz
4%
A) string1 == string2
58%
B) string1.equals(string2)
4%
C) string1 != string2
0%
D) string1.compareTo(string2) == 0
35%
E) ALL
Forwarded from < Ace Coding /> 🚀
🔹 When comparing strings in Java, what does the method compareTo() return?
Anonymous Quiz
44%
A) A boolean value (true or false)
33%
B) An integer value indicating the difference between the strings
11%
C) A string with a comparison message
11%
D) A String object with the lexicographical order of both strings
Forwarded from < Ace Coding /> 🚀
In Java string literals (like "hello") are automatically stored in a special memory region called the string pool. When we use a string literal directly in your code, the JVM checks if that string already exists in the string pool. If it does, it reuses the same reference (i.e., the same object). If it doesn't, it adds the string to the pool.
What Happens When You Use new String()?
If you create a string using the new String() constructor, you explicitly create a new object in memory, even if the content of the string is the same.
In this case, "hello" in the string pool and the new String("hello") object are not the same object in memory, so == will return false.
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String input = "hello";
System.out.println(input == "hello"); // True
What Happens When You Use new String()?
If you create a string using the new String() constructor, you explicitly create a new object in memory, even if the content of the string is the same.
String input = new String("hello");
System.out.println(input == "hello"); // falseIn this case, "hello" in the string pool and the new String("hello") object are not the same object in memory, so == will return false.
🌟🚀 @AceCoding Presents! 🚀🌟
When the Java compiler compiles the .java file, it will give you bytecode, which is an object file and executable on any machine with the JVM using just-in-time compilation. You can see this in action if you run a Java file in VS Code; it will make a .class file for the .java file.
@AceCoding
@AceCoding
Which one of the following has NOT been a name for Java?
Anonymous Quiz
3%
a) Oak
14%
b) Green
5%
c) Java
78%
d) Tree
what is the output of the ff.
float x = 2.2;
long y = 100;
System.out.println(x + y);
the new keyword is used to create new objects or instances of a class. It is essential for memory allocation in Java, as it initializes objects dynamically during runtime.
what is the output of the ff.
String ace = "Ace Coding";
System.out.println(ace.startsWith('A');
System.out.println(ace.endsWith('g');
for the above
Anonymous Quiz
67%
true, true
8%
true, false
14%
false, false
0%
false, true
11%
Error